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39 Cards in this Set

  • Front
  • Back
Nitrogen with 4 groups salt
Quaternary ammonium salt
N+R4 X-
Common name for phenylamine
Aniline
Ph-NH2
Properties of chiral amine (hybridization, etc.)
an amine with 3 diferent substituents is sp3 hybridized, tetrahedral and chiral.
HOWEVER, the amine will invert via SN2 reaction where it is temporarily sp2 hybridized, then returns to sp3 in reversed RS.
Barrier to this is similar to rotation about C=C bond
Basicity of amine (how is it measured)
RNH2 + H2O(acts as an acid) <> RNH3+ + OH-
a salt
The bacisity of RNH2 is measured via the ka of RNH3+
High Ka, low pKa- weak base
Low Ka, high pKa- strong base
Basicity trends for:
Ammonia, Primary, Sec, Tert, Aryl Amine
Heterocycles
pKa:
ammonia- 9.2
prim,sec,tert amines range of 10-11 (stronger than ammonia)
arylamine, heterocycles 0>6 weak bases
pyrolle almost 0
Bacisity of Amides,
why?
Not basic. Do not protonate
resonance form makes them electron poor, bad nucleophiles
Purification of amine + neutral compound(e.g. ketone)
dissolved in organic solvent
Add HCl, Amine is now mostly in its protonated salt form in the aqueous layer. Separate layers and neutralize > pure amine
Basicity of aryl amines, why less basic

What do substituent groups do?
Many resonance forms as NH2 is electron donating in the form of resonance. Protonation gets rid of resonance and destabilizes it.

Activating groups are electron donating, will make aryl-amine more basic

Deactivating groups lower basicity
Amine synthesis from RCOOH
RCOOH + SOCl2 >> + NH3> RCONH2 + LiALH4,Ether >
Preparation of Aryl Amines
Starting groups?
Aromatic group nitrated:
Aryl + HNO3 + H2SO4
Prep of amine from alkyl halide
1st degree
2nd degree
3rd degree

type of reaction
does it stop?
NH2 attacks RX > RNH3+ X- > NaOH > RNH2 primary
RNH2 attacks RX > R2NH2+ X- > NaOH> R2NH secondary
R2NH attacks RX> R3NH+ X- > NaOH> R3N tertiary
R3N attacks RX> R4N+ X- (quarternary ammonium salt)

SN2 reaction DOES NOT STOP! mostly will be primary and secondary though
? degree Amine prep from azide ion
Structure?
requirement for akyl?
RX + NaN3/Ethanol > RN=(N+)=(N-)
azide ion (N3)- attacks R, SN2
RN=(N+)=(N-) no longer nucleophilic,
RN=(N+)=(N-) + LiAlH4,ether/H2O> RNH2
1st degree, R must be 1st or 2nd degree
Gabriel synthesis of ? degree amines
Name of starting func. group?
alternate removal method?
RCONHCOR is an IMIDE
KOH/ethanol removes proton, nucleophile attacks R-X/DMF. completed via NaOH, H2O (hydrolisis)
ALTERNATIVELY
H2NNH2 and heat for final step, takes form CONHNHOC
RCONHCOR is an IMIDE
KOH/ethanol removes proton, nucleophile attacks R-X/DMF. completed via NaOH, H2O (hydrolisis)
ALTERNATIVELY
H2NNH2 and heat for final step, takes form CONHNHOC
Reductive Amination
process/mech
Ketone/Aldehyde + NH3/ H2/Ni(or NaBH4)
RCOR' > RCH(NH2)R'
can be repeated to yield secondary or tertiary amines
Features:
Ammonia attacks carbonyl carbon. OH and H are expelled. NH forms double bond, water leaves
NABH4 reduces to NH2
Alternate reagent for Reductive amination (why)
NaBH4 can reduce C=O so imine must be formed first
NABH3CN/methanol can only reduce C=N, instant reductive amination in one step!
Hoffman Rearrangement
Reactants/products
purpose
Mechanism
name/structure intermediate
what catalyzes decarboxylation
Convert amide into primary amine
RCONH2 + NaOH,BR2/H2O > RNH2 + CO2
Base removes acidic NH proton
N- attacks BR2 yielding RCONHBR + Br-
OH removes other H, rearranges to form RC(O-)=NBr
O- returns charge, Br leaves, R, bonds to N
(R-N=C=O + Br -) N attacks H-OH HO- attacks C
HOC(=O)-NHR N attacks HOH, H+ leaves,
RNH2 + CO2 + OH-

intermediate R-N=C=O is an isocyanate
decarboxylation via H2O catalyst
Reduction of RNO2 to RNH2
H2/Pt ethanol if no other groups can be reduced
if carbonyls present, use SNCl2,Acid, then NaOH
Curtis rearrangment
purpose
starting/ending
mechanism?
Converts acyl azide (RCON=(N+)=(N-) into RNH2 + CO2 + N2
RCOX + NaN3 > RCON3   
azide rearranges to (N-)-(N+)(trip)N
Heating:
R attacks N, Nattacks C, N2 leaves
isocyanate (R-N=C=O) decarboxylated via H2O
Converts acyl azide (RCON=(N+)=(N-) into RNH2 + CO2 + N2
RCOX + NaN3 > RCON3
azide rearranges to (N-)-(N+)(trip)N
Heating:
R attacks N, Nattacks C, N2 leaves
isocyanate (R-N=C=O) decarboxylated via H2O
Curtis rearrangement application in proteins?
Iocyanate + heat + (tert)-butyl-acohol or other to form Boc and Fmox
Acylation to form amide
what kinds of amines can be used?
whats can you do next?
RCOX + NH3 + pyridine solvent > RCONH2 + HCl
RCOX + RNH2 +solvent> RCONHR + HCl
RCOX +R2NH + solcent > RCONR2 + HCl
ammonia, primary and secondary react
LiALH4 to form amines
Hoffman elimination
purpose?
Mechanism?
E2 reaction
gets rid of amine, forms alkene
R-C(NH2)H-CH3 + Excess (CH3I)>> + Ag2O/H2O,heat > R-CH=CH2
OH- removes Hydrogen, C=C bond forms, quaternary ion leaves
H is taken from less substituted, less hindered C (non-zaitsev)
E2 reaction
gets rid of amine, forms alkene
R-C(NH2)H-CH3 + Excess (CH3I)>> + Ag2O/H2O,heat > R-CH=CH2
OH- removes Hydrogen, C=C bond forms, quaternary ion leaves
H is taken from less substituted, less hindered C (non-zaitsev)
Electrophilic substitution of Aryl amines
Br2 + ? ?
How is it controlled?
strongly ortho para directing, strongly activating
PH-NH2 + Br2 + H20 yields (2,4,6)tribromoanniline
to avoid this, reactions controlled via conversion to amide
NHAc Protecting group
structure
how is it formed
reactions
4-methyl-anniline + Ac2O(acetic anhydride/pyridine)>
yields methyl amide H3CCONH-toluene
Amide N lone pair is delocalized, so Br2 leads to monobromination at ortho position. Subsequent hydrolysis via NaOH,H2O yields 2-bromo-4methyl-anniline
Friedel crafts with Amide protecting group
Anniline + Acanhydride/pyridine > benzene amide > Ph-COCl/AlCl3 and subsequent hydrolisis via NaOH,H2O yields 4-aminobenzophenone
Sandmeyer reaction (functional group?)
useful for alkyl, aryl or both?
what is this process called?
purpose?
example
different Nus
diazonium salt Ar-(N+)tripN X-
only aryl
diazotization
anniline + HNO2 + H2SO4 > Ph-(N+)trip(N) -(HSO4) +2H2O
diazonium ion can be replaced by Nu in a sub rxn
HX + CuX is used unless X=I
p-methylaniline +HNO2/H2SO4 > pmethyldiazonium salt +HBr/CuBr> p-bromotoluene
If X=I, no need for CuX, just add NaI to diazonium salt
Also KCN can be used with CuCN to yield nitrile, then hydrolisis to add CO2H
NOT AN SN reaction
diazonium salt mechanism
HNO2 forms like acetic anhydride
Ph-NH-N=O + H+> Ph-N=N-O+H2 > Ph-(N+)tripN
HNO2 forms like acetic anhydride
Ph-NH-N=O + H+> Ph-N=N-O+H2 > Ph-(N+)tripN
Phenol formation
Ar-NH2 + HNO2 +H2SO4 > diazonium salt
+ Cu2O/(Cu(NO3)2,H2O > Ar-OH
Using Diazonium, then getting rid of it
Annilin + Br2> tribrominated anniline
+HNO2 + H2SO4 yields diazonium-benzene (2,4,6)tribromo + H3PO2 > 2,4,6tribromobenzene
Diazonium Coupling
what position?
mechanism?
Diazonium salt + Ph-Y (Y=OH- or -NR2)  in H2O> Ph-N=N-Ph-Y
will normally go para, but will go ortho if blocked
Diazonium salt + Ph-Y (Y=OH- or -NR2) in H2O> Ph-N=N-Ph-Y
will normally go para, but will go ortho if blocked
Azo dyes
structure?
function
Diazonium coupling where y= -N(Me)2
to give
Ph-N=N-Ph-N(Me)2
extended conjugated network absorbs visible light, works as dye
friedel crafts
Ph + RCOCl + AlCl3 > Ph-COR
Pyrolle basicity and reactivity
reaction with Br2
RNH+ pka of .4
amine and conjugated diene
N is sp2 hybridized, so lone pair is kept in p orbital, delocalized. VERY STABLE
Aromatic despite 5 memebered

When added to Br2, double bond attacks Br2 at C2 position (cation at C3 involves 3 resonance forms). If attack at C3, cation at C2 involves only 2.
Br- gets rid of H at C2. substituted Br at C2
Pyridine properties
basicity
reactivity
Sp2 hybridized, lone pair in sp2 orbital perpindicular to pi-bond system. More basic than pyrolle, but sp2 orbital has more s character, electrons less reactive.
substantial dipole moment due to lone paid and inductive effect of N. Very electron poor ring, deactivated
Pyrimidine
Less basic than pyridine because of inductive effects of second N
Imidazole
pKa of 7, more basic than pyrolle
indole
reactivity
like a pyrrole but with added phenyl group 
electrophillic addition takes place at C3
like a pyrrole but with added phenyl group
electrophillic addition takes place at C3
curtius rearrange for Boc
Diels Alder
conjugated diene + substituted alkene
aldehyde, ester, anhydride, nitrile
cyclic transition state forms ring simultaneously sp2 to sp3 hybridization
knovenegel
malonic ester + aldehyde no alpha h NaOet, dehydration, then h30+ to yield R-C=C-COOH