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29 Cards in this Set

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Cauchy-Shwartz Inequality

|x dot y| <=||x||* ||y||




Are equal when x = cy

Dot product

Scalar = a1b1 + a2b2 .... + anbn


||a||^2 = a dot a


Take dot product of two perpendicular vectors = 0


commutative


||a||*||b||cos(theta)

Triangle Inequality

||x + y|| <= ||x|| + ||y||

Angle between vectors

(a dot b) = ||a||* ||b||* cos(theta)

Determinant [ a b


c d]

det = ad - bc

Jacobian Matrix

Df(x,y) = [df1/dx df1/dy


df2/dx df2/y]

Chain Rule

D(f o g)(xo, yo) = Dfg(xo,yo) * Dg(xo,yo)


Rn to Rm to Rk


nxk matrix = kxm matrix times mxn matrix

Distance point to plane

|Ax + By + Cz +D| / (sqrt(A^2 + B^2 +C^2))




(p - b) dot n / ||n||


b is found with equation of the plane

Equation of a plane

Ax + By + Cz + D = 0




Normal vector (A,B,C)




A is slope of tangent vector in x-z plane


B is slope of tangent vector in y-z plane

Cross Product

cover up the one that you are trying to find, take det of remaining




det1 - det 2 + det3




a x b = 0 if they are colinear

j X k


k X i


i X j


crossed with itself



j X k = i


k X i = j


i X j = k


(flipped negative)


crossed with itself = 0

Partial derivatives

df/dx(x,y) = lim h to 0: (f(x+h, y) - f(x,y)) / h


df/dy(x,y) = lim h to 0: (f(x, y+h) - f(x,y)) / h

equation of tangent plane

gradient dot eqn of a plane

gradient

(df/dx, df/dy, df/dz)


normal to the tangent plane


points along the direction where f is increasing the fastes


perpendicular to level set

iterated partials:


d^2f/dxdy


d^2f/dydx


fxy


fyx

d^2f/dxdy = take x differential of y derivative


d^2f/dydx = take y differential of x derivative


fxy = take y differential of x derivative


fyx = take x differential of y derivative


mixed partials equal each other

Hessian matrix

matrix that contains all second partial derivatives of function top row with x first, bottom row with y first

Equation of the tangent line

l(t) = p + v(t)


p = point


v = perpendicular vector

How to find a perpendicular vector

Ex: (2,4)


Dot product must = 0, so 2x + 4y = 0


Arbitrarily find an x and y


Make it so that when you take the dot product both are 0

C1 and C2

Continuous and its derivatives are continuous

Directional derivative

gradient of f(a) dotted with v (unit vector) = a real number


lim h to 0: (f(x+hei) - f(x)) / h


ordinary derivative of a composite function

Good linear approximation

f(a) + f'(a) (t-a)

Multiply matrices

sum of first row and second column; each element multiplied by the corresponding element in the other matrix


# row A = # columns B

Boundary

Small ball epsilon around point where some lie in A and some do not

Closed/Open sets

Closed: contains all its boundary points


Open: contains none of its boundary points (some epsilon neighborhood entirely contained in a)

Epsilon/Delta definition

limit as x goes to a of f(x) = b, for any epsilon >0, there exists a delta >0, so that |x-a| < d and |f(x)-b| < E

Component functions

If components are continuous, so is function

Curves/Paths

Curve is one dimensional


path parametrizes the curve

Differentiable if

Df(xo) exists and


lim x to xo ||f(x)- Df(xo)(x-xo) - f(xo)|| / ||x-xo|| = 0

Local min/max

a is a critical point if gradient of f(a) = 0