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30 Cards in this Set
- Front
- Back
- 3rd side (hint)
Solve: 7x + 5 = 54
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x = 7
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If, when we add 5 to 7x we get 54. What must 7x have been before?
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Solve: 3x - 5 = 22
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x = 9
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If, when we subtract 5 from 3x we get 22. What must 3x have been before?
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Solve: 5x - 6 = 14
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x = 4
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If, when we subtract 6 from 5x we get 14. What must 5x have been before?
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Solve: 3x - 12 = 18
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x = 10
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If, when we subtract 12 from 3x we get 18. What must 3x have been before?
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Solve: 5x - 13 = 22
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x = 7
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If, when we subtract 13 from 5x we get 22. What must 5x have been before?
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Solve: 3x - 6 = -15
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x = -3
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If, when we subtract 6 from 3x we get -15. What must 3x have been before?
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Solve: 6x - 11 = -23
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x = -2
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If, when we subtract 11 from 6x we get -23. What must 6x have been before?
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Solve: 4x + 4 = 16
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x = 3
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If, when we add 4 to 4x we get 16. What must 4x have been before?
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Solve: 9x + 14 = 23
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x = 1
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If, when we add 14 to 9x we get 23. What must 9x have been before?
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Solve: 4x + 12 = 32
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x = 5
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If, when we add 12 to 4x we get 32. What must 4x have been before?
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Solve: 5(4x + 14) = 30
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x = -2
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When we multiply (4x + 14) by 5 we get 30. What must (4x + 14) have been before?
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Solve: 3(5x + 7) = 6
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x = -1
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When we multiply (5x + 7) by 3 we get 6. What must (5x + 7) have been before?
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Solve: 2(3x - 13) = -20
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x = 1
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When we multiply (3x - 13) by 2 we get -20. What must (3x - 13) have been before?
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Solve: 3(3x - 5) = 48
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x = 7
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When we multiply (3x - 5) by 3 we get 48. What must (3x - 5) have been before?
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Solve: 5(2x + 7) = 75
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x = 4
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When we multiply (2x + 7) by 5 we get 75. What must (2x + 7) have been before?
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Solve: 5(4x + 4) = 0
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x = -1
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When we multiply (4x + 4) by 5 we get 0. What must (4x + 4) have been before?
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Solve: 5(2x - 10) = -10
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x = 4
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When we multiply (2x - 10) by 5 we get -10. What must (2x - 10) have been before?
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Solve: 2(2x + 4) = 20
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x = 3
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When we multiply (2x + 4) by 2 we get 20. What must (2x + 4) have been before?
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Solve: 3(5x - 12) = 69
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x = 7
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When we multiply (5x - 12) by 3 we get 69. What must (5x - 12) have been before?
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Solve: 2(3x + 12) = 42
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x = 3
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When we multiply (3x + 12) by 2 we get 42. What must (3x + 12) have been before?
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Solve: 4x + 6 = 2x + 22
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x = 8
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Start by subtracting 2x from both sides...
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Solve: 5x + 13 = 3x + 7
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x = -3
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Start by subtracting 3x from both sides...
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Solve: 12x + 9 = 9x + 15
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x = 2
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Start by subtracting 9x from both sides...
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Solve: 4x + 9 = 3x + 10
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x = 1
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Start by subtracting 3x from both sides...
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Solve: 9x + 12 = 2x + 61
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x = 7
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Start by subtracting 2x from both sides...
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Solve: 5x + 5 = 2x + 2
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x = -1
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Start by subtracting 2x from both sides...
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Solve: 7x + 6 = 4x + 21
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x = 5
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Start by subtracting 4x from both sides...
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Solve: 8x + 10 = 4x + 6
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x = -1
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Start by subtracting 4x from both sides...
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Solve: 5x + 13 = 3x + 27
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x = 7
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Start by subtracting 3x from both sides...
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Solve: 5x + 6 = 4x + 14
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x = 8
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Start by subtracting 4x from both sides...
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